3(2x-1)^2-(2x-1)(2x+1)=4(2x+1)(x-3)

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Solution for 3(2x-1)^2-(2x-1)(2x+1)=4(2x+1)(x-3) equation: 



3(2x-1)^2-(2x-1)(2x+1)=4(2x+1)(x-3)

We move all terms to the left:

3(2x-1)^2-(2x-1)(2x+1)-(4(2x+1)(x-3))=0

We use the square of the difference formula

4x^2+3(2x-1)^2-(4(2x+1)(x-3))+1=0

We multiply parentheses ..

4x^2-(4(+2x^2-6x+x-3))+3(2x-1)^2+1=0



We calculate terms in parentheses: -(4(+2x^2-6x+x-3)), so:

4(+2x^2-6x+x-3)

We multiply parentheses

8x^2-24x+4x-12

We add all the numbers together, and all the variables

8x^2-20x-12

Back to the equation:

-(8x^2-20x-12)



We get rid of parentheses

4x^2-8x^2+20x+3(2x-1)^2+12+1=0

We add all the numbers together, and all the variables

-4x^2+20x+3(2x-1)^2+13=0

We move all terms containing x to the left, all other terms to the right

-4x^2+20x+3(2x-1)^2=-13

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